What is the number of amino acids encrypted in a portion of the gene containing 129 nucleotide residues - recognizable.

What a number of amino acids are encrypted in a portion of the gene containing 129 nucleotide residues

Answers to the question

Since 1 amino acid corresponds to 3 nucleotides (triplet), TO129: 3 = 43 - amino acids. Answer: 43 amino acids are encrypted in a portion of the gene.

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So, consider the tasks of the USE related to the cell's genetic code. You can find out these tasks on the issue of amino acid residues, triplets, nucleotides.

Task 1.

In the synthesis of protein, the IRNN molecule, the fragment of which contains 33 nucleotide residues. Determine the number of nucleotide residues in the DNA matrix circuit site.

Answer: 33.

Solution: On the principle of the IRNK concreteness, it is synthesized on the DNA matrix chain, the number of nucleotides will be the same.

Task 2.

The polypeptide section consists of 28 amino acid residues. Determine the number of nucleotides in the IRNN site containing information about the primary protein structure.

Answer: 84.

Solution: One amino acid is encoded by three nucleotides (triplet), therefore the correct answer is 28 * 3 = 84.

Task 3.

What number of amino acids are encrypted in a portion of a gene containing 129 nucleotide residues?

Answer: 43.

Solution: 1 amino acid is encoded with three nucleotides, so the amount of amino acids is: 129/3 = 43.

Task 4.

What number of TRNA participated in the synthesis of protein, which includes 130 amino acids? In response, write the appropriate number.

Answer: 130.

Solution: 1 TRNA transfers 1 amino acid, so their number is equally.

Task 5.

How many nucleotides make up one stop codon of INK?

Answer: 3.

Solution: Any Code of IRNK consists of three nucleotides, including stop codon.

Task 6.

How many nucleotides in the portion of the gene encoded a fragment of a protein of 25 amino acid residues? In response, write down only the appropriate number.

Answer: 75.

Solution: Three nucleotides (triplet) encode each amino acid (triplet), it means 25 amino acids encodes 75 nucleotides.

Task 7.

How many amino acids encodes 900 nucleotides? In response, write down only the appropriate number.

Answer: 300.

Solution: one amino acid is encoded 3 nucleotides, it means that 900 nucleotides = 300 triplets = 300 amino acids.

Task 8.

In the DNA molecule, the number of nucleotides with guanin is 20% of the total number. How many nucleotides in% with thimine in this molecule. In response, write down only the appropriate number.

Answer: 30%

Solution: According to the rule of complementarity, the amount of guanin is equal to the amount of cytosine, it means 20% (r + c = 40%), the thymine and adenine remains 60%, they are also equal to the amount, it means 30% (a = t = 30% ).

Task 9.

What percentage of nucleotides with a cytosine contains DNA if its adenine nucleotide share is 10% of the total number. In response, write down only the appropriate number.

Answer: 40%.

Solution: 10% adenine = 10% of thymine by complementarity rule. 80% remain on cytosine and guanin. And since their equal amount, then 40% of cytosine = 40% guanin.

Task 10.

What the number of nucleotides in the gene encodes the primary structure of a protein consisting of 300 amino acids. In response, write down only the appropriate number.

Answer: 900.

Solution: Three nucleotides (triplet) encode each amino acid. So, 300 amino acids encode 900 nucleotides.

Thus, it is clear how to solve the tasks of the EGE on biology on the coding of the genetic code. Three nucleotides encode each amino acid. If asking how many amino acids encodes n number of nucleotides, then you need this number n divided by 3.

Genetic code - task

If you ask how many nucleotides are needed to encode N amino acids. You need n multiply by 3, as one acid accounts for 3 nucleotides.

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